2[3(x+2)-(x+1)]=3(1+x)

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Solution for 2[3(x+2)-(x+1)]=3(1+x) equation:


Simplifying
2[3(x + 2) + -1(x + 1)] = 3(1 + x)

Reorder the terms:
2[3(2 + x) + -1(x + 1)] = 3(1 + x)
2[(2 * 3 + x * 3) + -1(x + 1)] = 3(1 + x)
2[(6 + 3x) + -1(x + 1)] = 3(1 + x)

Reorder the terms:
2[6 + 3x + -1(1 + x)] = 3(1 + x)
2[6 + 3x + (1 * -1 + x * -1)] = 3(1 + x)
2[6 + 3x + (-1 + -1x)] = 3(1 + x)

Reorder the terms:
2[6 + -1 + 3x + -1x] = 3(1 + x)

Combine like terms: 6 + -1 = 5
2[5 + 3x + -1x] = 3(1 + x)

Combine like terms: 3x + -1x = 2x
2[5 + 2x] = 3(1 + x)
[5 * 2 + 2x * 2] = 3(1 + x)
[10 + 4x] = 3(1 + x)
10 + 4x = (1 * 3 + x * 3)
10 + 4x = (3 + 3x)

Solving
10 + 4x = 3 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
10 + 4x + -3x = 3 + 3x + -3x

Combine like terms: 4x + -3x = 1x
10 + 1x = 3 + 3x + -3x

Combine like terms: 3x + -3x = 0
10 + 1x = 3 + 0
10 + 1x = 3

Add '-10' to each side of the equation.
10 + -10 + 1x = 3 + -10

Combine like terms: 10 + -10 = 0
0 + 1x = 3 + -10
1x = 3 + -10

Combine like terms: 3 + -10 = -7
1x = -7

Divide each side by '1'.
x = -7

Simplifying
x = -7

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